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TACOSDAILY
25.11.2021 •
Mathematics
√2 CSCꝊ - 2=0
Solve for if 0° ≤ < 360
(this is what I have so far)
Assuming your equation is square_root(2) * csc(x) -2 =0:
Add 2 to both sides: square_root(2)* csc(x) = 2
Divide both sides by square_root(2): csc(x) = 2/square_root(2) > csc(x) = square_root(2)
Write csc(x) as 1/sin(x): 1/sin(x) = square_root(2)
Cross-multiply: sin(x) *square_root(2) = 1
Divide by square_root(2) on both sides: sin(x) = 1/square_root(2) = square_root(2)/2
Now you have the equation: sin(x) = square_root(2)/2
Which angles on the unit circle have a sine equal to √(2)/2
Solved
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Ответ:
Both pure tessellations and regular tessellations are formed by repeating a single shape. However, regular tessellations are formed using only regular polygons (triangles, squares, or hexagons). Pure tessellations can be any shape that can be repeated without overlap or gaps.
Step-by-step explanation: