2) Find the height (to the nearest tenth) of an equilateral triangle with sides measuring 8 cm.

the height of the equilateral triangle is 6.9 cm

Step-by-step explanation:

In an equilateral triangle, all the sides are equal. Also all the angles are equal and each angle is 60 degrees. The bisectors of each of the angles would meet at the center of the triangle and each bisector divides the triangle into 2 equal right angle triangles as shown in the attached photo.

To determine h, the height of the equilateral triangle, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore,

8² = h² + 4²

64 = h² + 16

h² = 64 - 16 = 48

h = √48 = 6.9cm to the nearest tenth.

204 square meters

Step-by-step explanation:

The surface area of the 4 wall of the 1st prism is the product of perimeter and its height: (2+8)*2*2 = 40 m2

The surface area of the top and bottom of the 1st prism is the 2 times the product of its width and height: 2*8*2 = 32 m2

Therefore the total surface area of the 1st prism is: 40+32 = 72 m2

Similarly, the surface area of the 4 wall of the 2nd prism is the product of perimeter and its height: (2+3)*2*11 = 110 m2

The surface area of its top and bottom is: 2*3*2 = 12 m2

Therefore the total surface area of the 2nd prism is: 110 + 12 = 132 m2

Overall, the total surface area of the composite is 132 + 72 = 204 m2