g0606997
07.01.2021 •
Mathematics
2 planes leave the airport at the same time. their speeds are 140 mph and 170 mph and the angle between their courses is 25 degrees. how far apart are they after 2.5 hours
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Ответ:
183.27miles
Step-by-step explanation:
Note that we are considering two planes.
Plane 1
Speed = 140 mph
Time = 2.5 hours
Distance = ?
Speed = distance/time
140 mph = distance/2.5hrs
Distance = 140×2.5
= 350miles
Plane 2
Speed = 170 mph
Time = 2.5 hours
Distance = ?
Speed = distance/time
170 mph = distance/2.5hrs
Distance = 170×2.5
= 425miles
The angle between side is 25 degree
From cosine rule
c^2 = a^2 + b^2 − 2abcos(tetha)
Where a = 350
b = 425miles
c^2 = 350^2+425^2-2(350×425)(cos25)
c^2 = 122500+180625-297500(0.906)
c^2 = 303125-269535
c^2 = 33590
C = √33590
C = 183.27miles
The distance they flew apart after 2.5hrs is 183.27miles
Ответ:
then added 7. Hope this helps.