#3 Triangle inscribed in circle (Use 3.14 for pi)

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s108870

03.05.2020

Mathematics

answer: our required factorization will be

(3x+4)(x²-5)

step-by-step explanation:

since we have given that

$3x^3+4x^2-15x-20$

now, we will write it as :

$=\left(3x^3+4x^2\right)+\left(-15x-20\right)$

$\mathrm{factor\: out\: }-5\mathrm{\: from\: }-15x-20\mathrm{: \quad }-5\left(3x+4\right)$

so, we get

5(3x+4)

similarly,

$\mathrm{factor\: out\: }x^2\mathrm{\: from\: }3x^3+4x^2\mathrm{: \quad }x^2\left(3x+4\right)$

here, we get,

2(3x+4)

together it becomes,

$-5\left(3x+4\right)+x^2\left(3x+4\right)\\\\=\left(3x+4\right)\left(x^2-5\right)$

hence, our required factorization will be

(3x+4)(x²-5)

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