(3x^2)(4x)=12x^3 is 3x^2 a factor of 12x^3

(3x2 + 1) • (4x - 1)

Step-by-step explanation:

Equation at the end of step  1  :

(((12 • (x3)) -  3x2) +  4x) -  1

Equation at the end of step  2  :

(((22•3x3) -  3x2) +  4x) -  1

Checking for a perfect cube :

12x3-3x2+4x-1  is not a perfect cube

Trying to factor by pulling out :

Factoring:  12x3-3x2+4x-1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  4x-1

Group 2:  12x3-3x2

Pull out from each group separately :

Group 1:   (4x-1) • (1)

Group 2:   (4x-1) • (3x2)

Add up the two groups :

              (4x-1)  •  (3x2+1)

Final result :

(3x2 + 1) • (4x - 1)

Answer

2

Step-by-step explanation:

There are 2 cycles, one ends at pi and the other end at 2 pi