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DASASDAEDWEDA
24.05.2021 •
Mathematics
4) In A ABC, m B = 25°, b = 12 and c = 21. Find all possible m2 C to the
nearest degree.
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Ответ:
47.7° or 132.3°
Step-by-step explanation:
In A ABC, m B = 25°, b = 12 and c = 21. Find all possible mC to the
nearest degree.
We solve the above question using Laws of sines.
The formula is given as
b/sin B = c/sin C
b = 12
B = 25°
c = 21
C = ?
Hence:
12/sin 25 = 21/sin C
Cross Mulitiply
= 12 × sin C = sin 25 × 21
sin C = sin 25 × 21/12
C = arc sin (sin 25 × 21/12)
C = 47.7°
The second possible value of C =
180° - 47.7°
= 132.3°
Therefore, all the possible values of mC = 47.7° or 132.3°
Ответ:
x = 45
135°
Step-by-step explanation:
180 - 45 = 135
3x = 135
3x/3 = 135/3
x = 45