christinaS7696
12.03.2020 •
Mathematics
40 Points ♥ Trigonometry
The area of an isosceles triangle is 100cm².
Calculate the perimeter of the triangle given that one of the angles is π/6 rad.
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Ответ:
Case 1: 50.35 cm
Case 2: 56.715 cm
Step-by-step explanation:
AB = AC;
½ X AH x BC = 100 cm2
=> AH x BH = 100 cm2
=> AH = 100/BH
Case 1: (BAC)= /6
S = ½ x AB x AC x sin (BAC) = 100 cm2
AB^2 x sin /6 = 200
=> AB^2 x ½ = 200
=> AB = 20 cm = AC
BC^2 = AB^2 + AC^2 – 2 x AB x AC x cos (BAC) = 202 + 202 – 2 x 20 x 20 x /2 = (800 - 400) cm
=> BC = 10.35 cm
Perimeter: AB + AC + BC = 20 + 20 + 10.35 = 50.35 cm
Case 2: (ABC) = /6 => (BAC) = 2/3
S = ½ x AB x AC x sin (BAC) = 100 cm2
AB^2 x sin 2/3 = 200
=> AB^2 x /2 = 200
=> AB^2 = 400/
=> AB = AC = 15.197 cm
BC^2 = AB^2 + AC^2 – 2 x AB x AC x cos (BAC) = 400/ + 400/ – 2 x 400/ x (-1/2) = 692.82 cm
=> BC = 26.321
Perimeter: AB + AC + BC = 15.197 + 15.197 + 26.321 = 56.715 cm
Ответ:
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