6x+18=h(3x+9) what value the constant h in the equation shown below will result in a infinite number of solutions

h = 2

Step-by-step explanation:

6x  + 18  =  h (3x + 9)

To get the value of h, we simply need to make h subject of the formula;

To make h subject of the formula, we simply divide both-side of the equation by (3x + 9)

      =    

(On the right hand side of the equation (3x+2) will cancel out (3x+2) leaving us with h)

      =      h

h  =     ----------------(1)

We want to make the numerator and denominator look the same so that  we can cancel out, at the numerator, we can factor out 2 from 6x + 18

i.e 6x + 18 = 2 ( 3x + 9)

So we can  replace 6x + 18    by  2(3x + 9)  in equation (1)

h =

( on the right hand side of the equation, (3x + 9) will cancel out (3x + 9) leaving us with just 2)

h = 2

We can plug in our h =2 in the initial equation

6x +  18   =  2(3x + 9)

6x + 18 = 6x + 18

This equation has an infinite number of solutions.

Therefore the value of constant h in the equation that can make the equation have an infinite number of solutions is 2

When solving for X
~Add -4 to both sides
X+4Y=4
-4. -4

X=-4y+4

~add 4 to both sides
3x-4y+4=-4+4
3x=4y-4
~divide both sides by three
3x=4y-4
---
3. 3
X=3\4+ -4\3

When solving for Y
~add -x to both sides
x+4y+-x=4+-x
4y=-x+4
~divide both sides by 4
4yy=-x+4

4. 4
Y=-1\4x+1

3x-4y=-4
~add -3x to both sides
3x-4yy+-3x=-4+-3x
-4y=-3x-4

4. 4
Y=3\4x+1