Mathematics: 7,300 at 7% compounded semiannually for 3 years.

7,300 at 7% compounded semiannually for 3 years. - id7300731625508, anthonyhaywood

Ответ:

kennyjortiz

15.03.2022

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$7300\\
r=rate\to 7\%\to \frac{7}{100}\to &0.07\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annual, thus twice}
\end{array}\to &2\\
t=years\to &3
\end{cases}
\\\\\\
A=7300\left(1+\frac{0.07}{2}\right)^{2\cdot 3}\implies A=7300(1.035)^6$

and surely you know how much that is.

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Ответ:

naomicervero

13.01.2023

Mathematics

option A

Step-by-step explanation:

here's your solution

=> 6x - 7y = 28

=> - 7y = 28 - 6x

=> - y = 28/7- 6x/7

=> -y = 4 - 6x/7

=> y = 6x/7 - 4

hope it helps

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7,300 at 7% compounded semiannually for 3 years.

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