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TexaSuperdude
26.06.2019 •
Mathematics
9. the maximum horizontal range of a projectile is given by the formula r= u2/g where u is the initial velocity and g is the acceleration due to gravity. find the velocity with which a ball can be thrown to have a maximum range of 20 meters when the acceleration due to gravity is equal to 9.8 m/s.
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Ответ:
The answer is:
The velocity with which the ball can be thrown to have a maximum range of 20 meters is equal to 14 m/s.
![u=14\frac{m}{s}](/tpl/images/0018/1512/b3df2.png)
Why?To solve the problem and find the velocity, we need to isolate it from the equation used to calculate the maximum horizontal range.
We have the equation:
Where,
R is the maximum horizontal range.
u is the initial velocity.
g is the gravity acceleration.
Also, from the statement we know that:
So, using the given information, and isolating, we have:
Hence, we have that the velocity with which the ball can be thrown to have a maximum range of 20 meters is equal to 14 m/s.
Have a nice day!
Ответ:
The velocity with which a ball must be thrown to have a maximum range of 20 m is 14 m/s.
Note that this problem means to find the magnitude of the velocity and not the direction (it is implicit in the formula that the angle of the launch is 45°).
Explanation:
You just must use the given equation for the maximum horizontal range of a projectile and solve for u which is the unknwon:
Given equation: R = u² /gg = 9.8 m/s²R = 20 mu =?Solve for u:
u² = R × g = (20 m) × (9.8 m/s²) = 196 m²/s²Take square root from both sides:
u = 14 m/s ← answerОтвет:
is that the answer key for your quiz
Step-by-step explanation: