Mathematics: (98 ) can someone take a look at this? i m stumped. (answer choices provided) what is the fifth term of the geometric sequence? geometric sequence represented by a graph in quadrant 1 with n on x axis and a sub n on y axis. points at (1,81), (2,9), and (3,1). (graph attached) hint: an = a1(r)n − 1, where a1 is the first term and r is the common ratio

(98 ) can someone take a look at this? i m stumped.

Ответ:

dj4354

08.01.2022

Mathematics

a5 = 1/81

Step-by-step explanation:

(1,81) (2,9) (3,1)

The sequence goes

81,9,1,

We are multiplying by 1/9 each time

a1 = 81

r= 1/9

an = a1 r^(n-1)

an = 81 * (1/9) ^ (n-1)

The 5th terms

a5 = 81 * (1/9) ^ (5-1)

a5 = 81 * (1/9) ^4

a5 = 81/6561

a5 = 1/81

0,0(0 оценок)

Ответ:

rach1314

08.01.2022

Mathematics

$\bold{\bigg(5,\dfrac{1}{81}\bigg)}$

Step-by-step explanation:

(1, 81), (2, 9), (3, 1) means

a₁ = 81a₂ = 9a₃ = 1

the common ratio (r) is: 9 ÷ 81 → r = 1/9

therefore,

$a_4=\dfrac{1}{9}\cdot a_3\quad \rightarrow \quad a_4=\dfrac{1}{9}\cdot 1\quad \rightarrow \quad a_4=\dfrac{1}{9}\quad \rightarrow \quad \bigg(4, \dfrac{1}{9}\bigg)$ $a_5=\dfrac{1}{9}\cdot a_4\quad \rightarrow \quad a_5=\dfrac{1}{9}\cdot \dfrac{1}{9}\quad \rightarrow \quad a_5=\dfrac{1}{81}\quad \rightarrow \quad \bigg(5, \dfrac{1}{81}\bigg)$