tyreshagarrett123
29.11.2020 •
Mathematics
A ball is launched upward at 14 m/s from a platform 30 m high.Find the maximum height the ball will reach and how long it will take.
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Ответ:
The ball will reach a maximum height of 39.993 meters after 1.428 seconds.
Step-by-step explanation:
Let suppose that no non-conservative forces acts on the ball during its motion, then we can determine the maximum height reached by the Principle of Energy Conservation, which states that:
(1)
Where:
, - Initial and final translational kinetic energies, measured in joules.
, - Initial and final gravitational potential energies, measured in joules.
By definition of translational kinetic energy and gravitational potential energy we expand and simplify the expression above:
(2)
Where:
- Mass of the ball, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
, - Initial and final speed of the ball, measured in meters per second.
, - Initial and final heights of the ball, measured in meters.
The final height of the ball is determined by the following formula:
(3)
If we know that , , and , the maximum height that the ball will reach is:
The ball will reach a maximum height of 39.993 meters.
Given the absence of non-conservative forces, the ball exhibits a free fall. The time needed for the ball to reach its maximum height is computed from the following kinematic formula:
(4)
If we know that , and , then:
The ball will take 1.428 seconds to reach its maximum height.
Ответ:
1
Step-by-step explanation:
Given expression 2+(3-2x2)x1,
2+(3-2x2)x1
2 - 1 x 1 ^ Multiplication
2 - 1 ^ Multiplication
1 ^ Subtraction