A bicycle tire of radius 0.40 m and mass 1.7kg is rotating at 62.9 rad/s. What torque is necessary to stop the tire in 2.2 s?
Answer in units of N · m.
These are the last of my points, I have been scammed by people twice, someone please help me, this is actually physics but the scammers love physics.

T = taw

T = m r² ( w₂-w₁) / t

T = 1.7 × (0.40)² (0-62.9) / 2.2

T = 1.7 × 0.16 × -62.9 / 2.2

T = -17. 11 / 2.2

T = - 7.77 N.m

So, it's hard to know if the sides on the parallelogram are equal or not, but both a rhombus and square have four congruent sides, but only a square has four right angles.

So 1/2 shapes fit both parameters. Therefore there is a 50% probability it has four right angles, given that it has four congruent sides.