mscharris66
11.06.2021 •
Mathematics
A boat heading out to sea starts out at Point AA, at a horizontal distance of 804 feet from a lighthouse/the shore. From that point, the boat’s crew measures the angle of elevation to the lighthouse’s beacon-light from that point to be 12^{\circ} ∘ . At some later time, the crew measures the angle of elevation from point BB to be 2^{\circ} ∘ . Find the distance from point AA to point BB. Round your answer to the nearest foot if necessary.
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Ответ:
672 feets
Step-by-step explanation:
Using the solution diagram attached, the vertical height, h of the lighthouse ;
Using trigonometry :
Tanθ = opposite / Adjacent
Tan 2 = h / 804
h = tan 2 * 804
h = 28.076 feets
Using h, we can obtain the distance CB :
Tan θ = opposite / Adjacent
Tan 2 = 28.076 / CB
CB = 28.076 / Tan 12°
CB = 132.08860 feets
Distance between A and B
804 - 132.08860
= 671.9 feets
Ответ:
16²=16*16, 16= 4*4
4³=4*4*4
so:
Simplify: 16² = 16*16 = 4*4*4*4 = 4 = 4
4³ = 4*4*4 = 4*4*4 1
OR
256 ÷ 64 = 4