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19.02.2020 •
Mathematics
A certain brand of automobile tire has a mean life span of 36 comma 000 miles and a standard deviation of 2 comma 450miles.(Assume the life spans of the tires have a bell-shaped distribution.)(a) The life spans of three randomly selected tires are 34,000miles, 38,000 miles, and 31,000 miles. Find the z-score that corresponds to each life span.*For the life span of 34,000 miles, z-score is? (Round to the nearest hundredth as needed.)*For the life span of 38,000 miles, z-score is? (Round to the nearest hundredth as needed.)*For the life span of 31,000 miles, z-score is? (Round to the nearest hundredth as needed.)According to the z-scores, would the life spans of any of these tires be considered unusual? Yes or No(b) The life spans of three randomly selected tires are 33,550miles, 38,450 miles, and 36,000 miles. Using the empirical rule, find the percentile that corresponds to each life span.The life span 33,550 miles corresponds to the ?th percentile.The life span 38,450 miles corresponds to the ?th percentile.The life span 36,000 miles corresponds to the--- ?th percentile.
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Ответ:
Step-by-step explanation:
Let X be the mean lifespan of automobile tire
X is N(36,000, 2450)
The Z scores are calculated as (x-36000)/2450
xx-36000Z=(x-36000)/2450
34000-2000-0.816326531 =-0.82
3800020000.816326531 =0.82
31000-5000-2.040816327 =-2.04
No only if beyond |3| z score is there we say unusual
For 33550 miles
Z = -1
P(Z<-1) = 0.3413
So percentile is 34.13
For 36000 , z=0 so 50th percentile
Ответ:
wdym???
Step-by-step explanation: