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dkhakdoust
14.01.2021 •
Mathematics
A logarithmic function of base ‘3’ has a vertical asymptote at the line x=1. Its graph contains the point (2,1). What is the equation of the function?
1) f(x)=log3 (x+1)
2) f(x)=log3(x-1)+1
3) f(x)=log3(x+1)+1
4) f(x)=log3(x)+1
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Ответ:
9514 1404 393
2) f(x) = log3(x -1) +1
Step-by-step explanation:
The vertical asymptote of the log function is normally x=0. In this function, it is moved to the right 1 unit. That is accomplished by replacing the function argument x with (x-1). Only one answer choice matches:
f(x) = log3(x -1) +1
Ответ:
g ( 6 ) = 800 - 25 * 6 = 800 - 150 = 650Part C :f ( 7 ) = 1,500 * 0.88^7 = 613g ( 7 ) = 800 - 7 * 25 = 625f ( 7 ) ≈ g ( 7 )After approximately 7 months.