A negative charge of -4.0x10^-5C and a positive charge of 7.0x10^-5C are separate d by 0.15m. What is the force between the two charges?

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Ответ:

Tanya120

17.12.2020

Mathematics

From the given option the slope of the line -5/2 is shown by the equation $y=-\dfrac{5}{2}x-4$ that is option B) and this can be determined by using the slope-intercept form.

Given :

Equation -- $y=\dfrac{2}{5}x-1$ ---- (1)

First, determine the slope of the given line by using the slope-intercept form. The slope-intercept is given by the equation:

y = mx + c

Now, compare equation (1) with the above equation.

$\rm m_1 =\dfrac{2}{5}$

c = -1

For a line to be perpendicular to the other line the product of the slope of both the line is equal to -1, that is:

$\rm m_1m_2 = -1$

So, the slope of the line perpendicular to the line $y=\dfrac{2}{5}x-1$ is:

$\rm m_2 = -\dfrac{5}{2}$

So, from the given option the slope of the line -5/2 is shown by the equation $y=-\dfrac{5}{2}x-4$ that is option B).

For more information, refer to the link given below:

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A negative charge of -4.0x10^-5C and a positive charge of 7.0x10^-5C are separate d by 0.15m. What is the force between the two charges?​