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loloroyroy264
08.02.2021 •
Mathematics
A painter is painting a rectangular wall that measures 23.6 ft by 19.2 ft. Each gallon can of paint covers 200 square feet. What are the fewest gallons needed to paint the wall?
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Ответ:
3 gallons
Step-by-step explanation:
Length of the rectangular wall = 23.6 feet
Width of the rectangular wall = 19.2 feet
Surface area of the wall = 23.6 × 19.2
= 453.12 square feet
∵ 200 square feet of the wall is covered by the amount of paint = 1 gallon
∴ 1 square feet of the wall will be covered by the amount of paint =
gallons
∴ 453.12 square feet will require the amount of paint =![\frac{453.12}{200}](/tpl/images/1100/9045/143eb.png)
= 2.2656 gallons
Therefore, minimum 3 gallons will be required to paint the wall.
Ответ: