A parallelogram is shown below: A B A 2 foot D с 3 feet Part A: What is the area of the parallelogram? Show your work. (5 points) Part B: How can you decompose this parallelogram into two triangles? If this parallelogram was decomposed into two triangles, what would be the area of each triangle? (5 points)​

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  Part A: 2 ft²

  Part B: draw a diagonal (AC, for example); 1 ft²

Step-by-step explanation:

Part A:

The area of a parallelogram is given by the formula ...

  A = bh

where 'b' is the length of the base, and 'h' is the perpendicular distance between the bases.

Using the numbers shown on the diagram, the area is ...

  A = (3 ft)(2/3 ft) = 3·2/3 ft²

  A = 2 ft² . . . . . area of the parallelogram

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Part B:

Typically, a polygon is partitioned into triangles by drawing diagonals from one of the vertices. It does not matter which one. (In a quadrilateral, only one diagonal can be drawn from any given vertex.) Here, the "base" of each triangle is the same as the base of the parallelogram: 3 feet. The "height" of each triangle is the same as the height of the parallelogram: 2/3 ft.

The area of a triangle is given by the formula ...

  A = 1/2bh

  A = 1/2(3 ft)(2/3 ft) = (1/2)(3)(2/3) ft²

  A = 1 ft² . . . . . . . . area of each triangle

Additional comment

It should be no surprise that the area of each of the two congruent triangles is 1/2 the area of the parallelogram.

Step-by-step explanation:

Given that :

Jack had 4 hours of school.

He spent 45 minutes in the library

1/2 hour on a science lecture  and;

had a lunch break of 25 minutes

The objective is to determine how much time is left for the school to get over and we are to write the answer as a fraction.

In order to do that, we will have to convert the minutes into hours,

we all know that; 60 minutes = 1 hour.

Then,

45 minutes = (45/60)hour = 3/4 hour

25/60 minutes = 1/4 hour

Therefore, the amount of time left  for the school to get over is:

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