evarod
22.04.2020 •
Mathematics
A particle is moving along a projectile path at an initial height of 80 feet with an initial speed of 112 feet per second this can be represented by the function H(t) = 16t^2 + 112t + 80 what is the maximum height of this particle ?
A) 196 feet
B) 276 feet
C) 392 feet
D) 472 feet
Solved
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Ответ:
131,072π/3 or approximately 137,358.3
Step-by-step explanation:
V = 4/3 x π x r^3
V = 4π/3 x (32^3)
V = 131072π/3 ft^3
V = 137,258.3 ft^3