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FailingstudentXD
19.11.2020 •
Mathematics
A particle moves on the hyperbola xy=15 for time t≥0 seconds. At a certain instant, x=3 and dx/dt=6. Which of the following is true about y at this instant?
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Ответ:
Step-by-step explanation:
Given information:
The particle moves on the hyperbola![xy=15](/tpl/images/0913/1462/73329.png)
Time![t\geq 0](/tpl/images/0913/1462/4b570.png)
Now at a certain instant ,
and ![\frac{dx}{dt} = 6](/tpl/images/0913/1462/d3905.png)
Now, Differentiating
with respect to ![t](/tpl/images/0913/1462/3d334.png)
We get:
Now substitute the values in above equation:
The negative sign indicates that
is decreasing by 10 units per second.
For more information visit:
link
Ответ:
The particle follows hyperbolic path. The value of
is decreasing at the rate of
units per seconds.
Given: A particle moves on the hyperbola
for time
seconds. At a certain instant,
and
.
According to question,
hyperbola curve is
.
Differentiating the curve w.r.t
we get:
Now substituting the values are
and
.
Therefore,
is decreasing
units per seconds.
Learn more about differentiation here:
link
Ответ:
Step-by-step explanation:
From the information being provided;
We learnt that Becky pays simple interest at an annual interest rate of 8.8% which is calculated quarterly.
i.e.![\dfrac{8.8\%}{4}= 2.2\%](/tpl/images/0827/8445/27998.png)
Since the first payment of $27,000 happened in the first three months, therefore, Becky will be able to have the money in the bank for 3 quarters prior to the lump-sum payment gets started.
Thus, the estimate of the amount Becky would earn as interest during this period of time is as follows:
I = $1,782