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matluck7956
16.06.2020 •
Mathematics
a person invest in 9000 in a bank. the bank pays 5% interest compounded semi annually. to the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 14800 dollars
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Ответ:
10.1 years.
Step-by-step explanation:
It is given that,
Principal = 9000
Rate of interest = 5%
No. of times interest compounded = 2 times in an year
Amount after certain time = 14800
The formula for amount:
where, P is principal, r is rate of interest, n is no. of times interest compounded in an year and t is time in years.
Substitute the given values in the above formula.
Taking log both sides.
Therefore, the required time is 10.1 years.
Ответ:
y = 9, z = 8
Step-by-step explanation:
Here, the given equations are,
150x + 80y + 12z = 2,466 (1)
380x + 95y + 48z = 5,419 (2)
210x + 130y + 60z = 3,960 (3)
4 × equation (1) - Equation (2),
220x + 225y = 4,445 (4)
5 × equation (1) - equation (3),
540x + 270y = 8,370
⇒ 270 y = 8370 - 540 x
⇒ y = 31 - 2 x
Substituting the value in equation (4),
220 x + 225 ( 31 - 2 x ) = 4445
220 x + 6975 - 450 x = 4445
- 230 x = - 2530
x = 11
By putting this value in equation (5),
we get, y = 31 - 22
y = 9
By putting the value of x and y in equation (1),
1650 + 720 + 12 z = 2466
2370 + 12 z = 2466
12 z = 96
z = 8