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allyfurby
27.03.2020 •
Mathematics
A projectile is shot upward from the surface of Earth with an initial velocity of 106 meters per second. Use the position function below for free-falling objects. What is its velocity after 5 seconds? After 13 seconds? (Round your answers to one decimal place.) s(t) = −4.9t2 + v0t + s0
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Ответ:
Step-by-step explanation:
The velocity of the object is the derivative of its position, so is ...
s'(t) = -9.8t +v0 = 106 -9.8t
At the given times, the object's velocity is ...
s'(5) = 106 -9.8·5
s'(5) = 57 . . . . m/s
s'(13) = 106 -9.8·13
s'(13) = -21.4 . . . . m/s
After 5 seconds, its velocity is 57 m/s; after 13 seconds, -21.4 m/s.
Ответ:
¿Alguien sabe traducir español?
Step-by-step explanation: