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Schoolworkspace453
04.12.2020 •
Mathematics
A race car accelerates uniformly from 18.5 m/s to 50.5 mys in 2.45 seconds. Determine the acceleration of the car.
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Ответ:
79.78 m.
Step-by-step explanation:
The acceleration is 11.17 m/s^2.
The distance traveled is 79.78 m.
Acceleration is change of velocity over time. The change of velocity is from 18.5 to 46.1 m/s or 46.1 - 18.5 = 27.6 m/s. The time of change is 2.47 s. So the acceleration is 27.6 m/s / 2.47 s = 11.17 m/s^2.
The distance traveled is average velocity times time of travel. Average velocity is 1/2 of the change of velocity added to the initial velocity, or 1/2•[final velocity (46.1 m/s) - initial velocity (18.5 /s)] + 18.5 m/s or 1/2•27.6 m/s + 18.5 m/s = 32.3 m/s. The time of travel is 2.47 s. So the distance traveled is average velocity 32.3 m/s times 2.47 s = 79.78 m.
Ответ:
5b = 10
Hope this helps
:)