olivia0420
14.04.2020 •
Mathematics
A random sample of 100 visitors to a popular theme park spent an average of $142 on the trip with a standard deviation of $47.50. Which of the following would be the 98% confidence interval for the mean amount of money spent by all visitors to this theme park?
a. ($130.77, $153.23)
b. ($132.77, $151.43)
c. ($132.69, $151.31)
d. ($140.88, $143.12)
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Ответ:
a) 98% confidence interval for the mean amount of money spent by all visitors to this theme park
($130.77, $153.23)
Step-by-step explanation:
Explanation:-
Given sample size 'n' = 100
Given the average of $142 on the trip with a standard deviation of $47.50
mean of the sample (x⁻) = $142
standard deviation σ = $47.50.
Confidence intervals:-
The 98% of confidence intervals
on calculation, we get
($130.95 , 153.04)
The confidence intervals are ($130.95 , 153.04)
Final -
Its nearly the given option its (a)
($130.77, $153.23)
Ответ: