A rectangle has perimeter 64 feet, and it’s area is 247 sq-feet.Find the dimension of this rectangle

  13 ft by 19 ft

Step-by-step explanation:

If we represent length and width by x and y, we can write the equations for perimeter and area as ...

  P = 2(length + width)

  64 = 2(x +y)

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  A = length × width

  247 = xy

These equations can be easily solved with a graphing calculator. The solutions are ...

  (x, y) = (13, 19) or (19, 13).

Either way, the rectangle has dimensions 13 ft by 19 ft.

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If you like you can solve the second equation for y, then substitute that into the first equation.

  y = 32 -x

  247 = x(32 -x)

  x^2 -32x +247 = 0

  (x -13)(x -19) = 0

One dimension is either 13 ft or 19 ft. The corresponding other dimension is 19 ft or 13 ft.