Mathematics: A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Find the time that the rocket will hit the ground, to the nearest 100th of second. Y=-16x^2+189x+79

In polar coordinates, we haveFrom this we can writeIf , then , so we get...

A rocket is launched from a tower. The height of

Ответ:

hii4199

07.02.2022

Mathematics

Step-by-step explanation:

Given the height of the rocket y in feet related to time after launch x related by the equation:

Y=-16x^2+189x+79

The rocket will hit the ground when y = 0

The equation will become:

0=-16x^2+189x+79

Rearrange

-16x^2+189x+79 = 0

multiply though by minus

16x^2-189x-79 = 0

Factorize and solve for x:

x = 189±√189²-4(16)(-79)/2(16)

x = 189±√35721+5056/32

x = 189±√40777/32

x = 189±201.93/32

x = 189+201.93/32

x = 390.93/32

x = 12.22secs

hence the rocket will hit the ground after 12.22seconds (to the nearest hundredth of a sec)

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Ответ:

camilacarrielh15

08.06.2021

Mathematics

In polar coordinates, we have

$x=r\cos\theta\implies\cos\theta=\dfrac xr$
$y=r\sin\theta\implies\sin\theta=\dfrac yr$

From this we can write

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac yr}{\frac xr}=\dfrac yx$

If $\theta=\dfrac{4\pi}3$ , then $\tan\theta=\sqrt$ , so we get

$\dfrac yx=\sqrt3\implies y=\sqrt3\,x$

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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Find the time that the rocket will hit the ground, to the nearest 100th of second. Y=-16x^2+189x+79

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