tadopson2003
14.08.2020 •
Mathematics
A set of 9 numbers has a mean of 20. What additional number must be included in this set to create a new set with a mean that is 4 less than the mean of the original set?
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Ответ:
Greetings from Brasil...
The average for a set of 9 elements will be
(A + B + C + D + E + F + G + H + I) ÷ 9 = 20
Let's make (A + B + C + D + E + F + G + H + I) like S
(I chose S to remember a sum)
Let us think
S ÷ 9 = 20
S = 20 × 9
S = 180
So, (A + B + C + D + E + F + G + H + I) = 180
According to the statement, we will include a number (element J) in the sum to obtain a mean of (20 - 4), that is:
(A + B + C + D + E + F + G + H + I + J) ÷ 10 = (20 - 4)as seen above, (A + B + C + D + E + F + G + H + I) = 180, then
(180 + J) ÷ 10 = 16
(180 + J) = 160
J = 160 - 180
J = - 20So, including the number - 20 (minus 20) in the original mean we will obtain a new mean whose result will be 16
Ответ:
u
Step-by-step explanation: