A train leaves L.A. at 2pm and heads north at 50mph. If the next train leaves the station 3 hours later and heads north at 60 mph, what time will the second train catch up with the first?

8 AM

Step-by-step explanation:

Start time = 2 PMSpeed of the first train = 50 mphSpeed of the second train = 60 mphTrains head same directionThe second train spends 3 hour less time than the first but both take same distance

Let the time in travel for the first train be x, then we have equation for distance:

50x = 60(x - 3)50x = 60x - 18060x - 50x = 18010x = 180x = 18 hours

Time when the second train caches up the first one:

2 PM + 18 hours = 8 AM next day

Total possible outcomes = 6 x 6  = 36

Listed here are all the possible 36 outcomes:
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

Total outcomes that have a sum greater than 6 = 21

Listed here are the possible outcome greater than 6:
(1,6)(2,5)(2,6)(3,4)(3,5)(3,6)(4,3)(4,4)(4,5)(4,6)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

P(sum greater than 6)  = 21/36 = 7/12

P(sum greater than 6) = 7/12