chloesmolinski0909
15.01.2020 •
Mathematics
A? twin-engined aircraft can fly 1064 miles from city a to city b in 4 hours with the wind and make the return trip in 7 hours against the wind. what is the speed of the? wind?
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Ответ:
Wind speed = 159.6 miles per hour.
Step-by-step explanation:
The distance is the same so some sort of basic equation can be made.
Givens
From A to B
t = 4 hours
v = p + w
d = 1064
From B to A
t1 = 7 hours
v = p - w
d = 1064
Equation
t * (p + w) = t1 * ( p - w)
Solution
4(p + w) = 7(p - w)
4p + 4w = 7 p - 7w
Add 7w to both sides.
4p + 4w + 7w = 7p
4p + 11w = 7p
Subtract 4p from both sides
11w = 7p - 4p
11w = 3p
Divide by 3
p = 11w/3
4P + 4W = 1064
11w/3 + 3W = 1064
w(3.6667 + 3) = 1064
W*6.666667 = 1064
W = 1064 / 6.666667
W = 159.6 mph
Ответ:
the answer is B.) Julia
Step-by-step explanation: