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jazprincezz7606
25.12.2019 •
Mathematics
A. y-2=2(x-3)
b. y-3=2(x-2)
c. y-10=2(x-1)
d. y-1=2(x-10)
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Ответ:
Step-by-step explanation:
The point-slope form of an equation of a line:
m - slope
(x₁, y₁) - point
The formula of a slope:
We have the points (-3, 2) and (1, 10). Substitute:
Using the point (-3, 2):
Using the point (1, 10):
Ответ:
C. y-10=2(x-1)
Step-by-step explanation:
We have two points on the line, we can find the slope
m = (y2-y1)/(x2-x1)
= (10-2)/(1--3)
= 8/(1+3)
=8/4
=2
The slope is 2
We can use point slope form using the point (1,10)
y-y1 = m(x-x1)
y-10 = 2(x-1)
Ответ:
The correct answer is: [A]: " All rectangles are quadrilaterals. "
Step-by-step explanation:
The other answer choices:
B, C, and D — are incorrect.
Not all "quadrilaterals" (which are "4-sides polygons") can be classified as {merely types of}: "rectangles" ; or "parallelograms" ; or "squares".
It is true that All of the shapes — rectangles, parallelograms, and squares — which are mentioned in Answer choices: [B], [C], and [D] , respectively — are, in fact, types of quadrilaterals .
However, there are other types of quadrilaterals as well.
For instance, all "rhombuses", or "rhombi", and all "trapezoids" — as well as "kites" and 4 (four)-sided "arrowheads" are quadrilaterals, as well.
Furthermore, the choices provided within Answer choices: [B]. {C] and [D]; are too limited in scope for other reasons, as well. Read the following for more information and explanation.
Note that all "squares" are "rectangles", yet not all "rectangles" are "squares". All "squares" are "rhombuses" (or, "rhombi"); as well as "parallelograms", yet not all "rhombuses" ["rhombi"] are squares — and not all parallelograms are squares.
As such, all "rectangles" are "parallelograms", yet not all "parallelograms" are rectangles.
Note that all "rhombuses" {"rhombi"] are "parallelograms", yet not all "parallelograms" are "rhombuses" ["rhombi"].
Hope this is helpful to you.
Best wishes to you in your academic pursuits
— and within the community!