A15-foot ladder is leaning against a house. the base of the ladder is 4 feet from the house. to the nearest tenth of a foot, how high does the top of

The correct question is
A 15-foot ladder is leaning against a house. the base of the ladder is 4 feet from the house. to the nearest tenth of a foot. How high up the house does the ladder reach?

see the picture attached to better understand the problem

applying the Pythagoras Theorem
15²=4²+h²-----> h²=15²-4²-----> h²=225-16----> h=√209
h=14.46 ft------> h=14.5 ft

the answer is
14.5 ft

19 cm

Explanation:

to answer this question, we should remind the difference between distance and displacement:

- the distance covered by an object is the sum of all movements made by the object, regardless of their directions

- the displacement of an object is just the difference in position between its final point and its starting point

Based on these definitions, we can now calculate the distance covered by the car, which has moved 9 cm, then 4 cm and then 6 cm. The distance is just the sum of these values: