Mathematics: Abag has 2 green marbles, 3 red marbles, and 3 yellow marbles. what is the probabilty that you pick a yellow marble, do not replace it, and pick another yellow marble? 3/28 1/28 9/56 1/8

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Abag has 2 green marbles, 3 red marbles, and 3 - id2333850930, kianadomingo2806

Ответ:

nardosem9

10.01.2022

Mathematics

Probability of picking 2 yellow marbles WITHOUT REPLACEMENT

= $\frac{3}{28}$

Step-by-step explanation:

Number of green marbles = 2

Number of red marbles = 3

Number of yellow marbles = 3

So, the total number of marbles = 2 + 3 + 3 = 8 marbles

Let E : Event of picking a yellow marble from the bag

Now, Probability of an Event E = $\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}$

⇒ Here, $P(E) = \frac{3}{8}$

After picking 1 yellow marble from the bag:

Total marbles left in bag = 8 -1 = 7

Total yellow marbles left in bag = 3 - 1 = 2

Now, the probability of picking the second yellow marble WITHOUT REPLACEMENT = $\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}} = \frac{2}{7}$

So, the Probability of picking 2 yellow marbles WITHOUT REPLACEMENT

= $\frac{3}{8} \times \frac{2}{7} = \frac{6}{56} = \frac{3}{28}$

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Abag has 2 green marbles, 3 red marbles, and 3 yellow marbles. what is the probabilty that you pick a yellow marble, do not replace it, and pick another yellow marble?
3/28
1/28
9/56
1/8

Ответ:

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