Mathematics: ABCD is a quadrilateral Work out angle x

ABCD is a quadrilateral Work out angle x

RayOfSunsh1ne

24.01.2022

First of all, we can work out the length of BD: using the pythagorean theorem, we have

$BD = \sqrt{6^2+8^2}=10$

Now, we can work on triangle BCD and use the sine theorem: we have

$\dfrac{BD}{\sin(\hat{C})} = \dfrac{CD}{\sin(x)}$

Plugging the values and solving for $\sin(x)$ we have

$\dfrac{10}{\sin(29)} = \dfrac{13}{\sin(x)} \iff \sin(x)=\dfrac{13\cdot \sin(29)}{10}\approx 0.63$

We deduce

$x=\arcsin(0.63)\approx 39$

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pablogonzaleztellez

14.04.2020

A (-27a^3b^6 + 8a^9b^2)

Step-by-step explanation:

For edge

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