gmedisa08
14.08.2019 •
Mathematics
Abin contains 78 light bulbs of which four are defective. if five are randomly selected from the bin without replacement, find the probability that all five are not defective.
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Ответ:
0.7630
Step-by-step explanation:
Probaility of defective = 4/78
Probability of NOT defective = 1 - 4/78 = 74/78
Note: probability of NOT A = 1 - probability of A
Since without replacement, we need to consider that with each turn, 1 goes down from total and we multiply all the 5 outcomes, hence:
Probability 5 not defective =
THis is the answer, 0.7630
Ответ: