Abird is in a tree 30 feet off the ground and drops at twigs at lands on a rose bush 25 ft below. the function h(t)=-16t^2+30, where t represents the time in seconds gifts the height h and feet of the twig above the ground as it falls when will the twig land on the bush

It will land on the bush after 1.25 seconds.

First, we will start with what we are given the equation: h(t) = -16t^2 + 30

Now, we should input a 5 for the h(t) because we want the seconds that will give us a height of 5 seconds.

5 = -16t^2 + 30

Solve the equation:
0 = -16t^2 + 25

To solve this, you could use the quadratic formula or factor out a -1 and you will have the difference of two squares.

Either way the answer is 1.25 seconds.

After 1.25 seconds the twig land on the bush.

Step-by-step explanation:

Given function that shows the height of twig from the ground after t seconds,

When twig is on the bush,

h(t) = 5 feet   ( ∵ the distance from bush to ground = 30 - 25 = 5 feet )

 

Since, time can not be negative,

Hence, t = ≈ 1.25

Therefore, after 1.25 seconds the twig land on the bush.

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