Abox contains 144 marbles, which are either red or blue. if there are 3 times as many red marbles as there are blue marbles in the box, how many red marbles are in the box

Given:
X: The blue marbles.
3X: The red marbles.
A box contains 144 marbles.
SOLVING:
X + 3X = 144
4X = 144
X =
X = 36 ===> The blue marbles.

If there are 3 times as many red marbles as there are blue marbles:
3(36) = 108 ===> The red marbles. SOLUTION

TESTING:


GOOD LUCK...!!!

B = 12.8 cm (to 1.d.p)

D = 24.1 cm (to 1.d.p)

Step-by-step explanation:

Using Pythagoras Theorem:

B: 4^2 + 3.5^2 = 28.25

square root 28.25 = 5.3 (to 1 decimal place) so this is the length of the missing side.

To find perimeter add sides a, b and c so...

perimeter of triangle B = 12.8 cm (to 1 decimal place)

D: 10^2 - 6.5^2 = 57.75

square root 57.75 = 7.6 (to 1 decimal place) so this is the length of the missing side.

To find perimeter add sides a, b and c so...

perimeter of triangle D = 24.1 cm (to 1 decimal place)

^2 indicates squared

Sorry but I'm not too sure / confident about A or C