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taylordalton93
02.07.2020 •
Mathematics
According to a 2009 Reader's Digest article, people throw away approximately 13% of what they buy at the grocery store. Assume this is the true proportion and you plan to randomly survey 101 grocery shoppers to investigate their behavior. What is the probability that the sample proportion exceeds 0.16?
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Ответ:
The probability that the sample proportion exceeds 0.16 is 0.2061.
Step-by-step explanation:
We are given that according to a 2009 Reader's Digest article, people throw away approximately 13% of what they buy at the grocery store.
You plan to randomly survey 101 grocery shoppers to investigate their behavior.
Let
= sample proportion
The z-score probability distribution for the sample proportion is given by;
Z =
~ N(0,1)
where,
= sample population = 0.16
n = sample of grocery shoppers = 101
Now, the probability that the sample proportion exceeds 0.16 is given by = P(
> 0.16)
P(
> 0.16) = P(
>
) = P(Z > 0.82) = 1 - P(Z
0.82)
= 1 - 0.7939 = 0.2061
The above probability is calculated by looking at the value of x = 0.82 in the z table which has an area of 0.7939.
Ответ:
1341.75
Step-by-step explanation: i did the math boisss :)