Acircle has a diameter with endpoints (-8, 2) and (-2, 6). what is the equation of the circle? r2 = (x - 3)2 + (y + 4)2 r2 = (x - 5)2 + (y + 4)2 r2 = (x + 5)2 + (y - 4)2 r2 = (x + 3)2 + (y - 4)2

Step-by-step explanation:

we know that

The equation of the circle into center-radius form is equal to

where

(h,k) is the center of the circle

r is the radius of the circle

Step 1

we have

Find the center of the circle

The center of the circle is the midpoint between point A and point B

The formula to calculate the midpoint is equal to

substitute the values

the equation of the circle is equal to

D) 32π in³

Step-by-step explanation:

First, we find out what r is.

We can do that because we know the area when the radius is r.

This equation can be made: 4π = 4/3*πr³

The π's and the 4 cancel out, which gives us: 1 = 1/3r³

This gets us 3 = r³ --> r = ∛3 (distance can't be negative)

Now, we can plug that into the equation again: V = 4/3*π(2*√3)³

(2∛3)³ = 24 --> V = 4/3*π*24 --> V = 96/3*π --> V = 32π in³