Mathematics: Acoordinate plane with a line passing through the points (negative 4, negative 5) and (1, negative 1). write an equation in standard form of the line that is graphed. then find the x- and y-intercepts. the equation of the line in standard form is . the x-intercept is . the y-intercept is .

Acoordinate plane with a line passing through the

Ответ:

Aquaflash

12.06.2020

Mathematics

4x - 5y - 9 = 0

$\frac{9}{4}$

$\frac{-9}{5}$

Step-by-step explanation:

The equation of a straight line passing through the points (-4,-5) and (1,-1) is given by $\frac{y - (-5)}{-5-(-1)} =\frac{x-(-4)}{-4-1}$

⇒ $\frac{y+5}{-4} =\frac{x+4}{-5}$

⇒ 5y + 25 = 4x + 16

⇒ 4x - 5y - 9 = 0 ....(1) (Answer)

Now, this above equation can be represented as

$\frac{x}{\frac{9}{4} } + \frac{y}{\frac{-9}{5} } =1$

Therefore, the x-intercept is $\frac{9}{4}$ (Answer)

And the y-intercept is $\frac{-9}{5}$ . (Answer)

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Ответ:

cuzhernamesari

18.04.2023

Mathematics

To make things easier, turn 2 2/3 into 8/3. Then use "same change flip" to change 60 divided by 8/3 into 60(same) times(change) 3/8(flip). and the answer would be 22 1/2.

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Acoordinate plane with a line passing through the points (negative 4, negative 5) and (1, negative 1).
write an equation in standard form of the line that is graphed. then find the x- and y-intercepts.

the equation of the line in standard form is .

the x-intercept is .

the y-intercept is .

Ответ:

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