Afruit stand has to decide what to charge for their produce. they need $5.30/$5.30 for 11 apple and 11 orange. they also need $7.30/$7.30 for 11 apple and 22 oranges. we put this information into a system of linear equations. can we find a unique price for an apple and an orange?

Yes, we can find a unique price for an apple and an orange.

Step-by-step explanation:

Let x be the price of one apple and y be the price of one orange.

We have been given that a fruit stand has to decide what to charge for their produce. They need $5.30 for 1 apple and 1 orange.

We can represent this information in an equation as:

They also need $7.30 for 1 apple and 2 oranges.

Upon substituting our given information we formed a system of equations. Let us see if this system is solvable or not.

For a unique solution , where and are constant of x and y variables of 1st equation respectively. and are constant of x and y variables of 2nd equation respectively.

Let us check our system of equations for unique solution.

We can clearly see that 1 is not equal to half, therefore, we can find a unique price for an apple and orange using our system of equations.

Upon subtracting our 1st equation from 2nd equation we will get,

Therefore, price of one orange is $2.

Upon substituting y=2 in equation 1 we will get,

Therefore, price of one apple is $3.30.

Translations are transformations that change the position of the graph of a function. The general shape of the graph of a function is moved up, down, to the right or to the left. The translations are considered rigid transformations.

 Suppose that k> 0

 To graph y = f (x) + k, move the graph of k units up.

 To graph y = f (x) -k, move the graph of k units down.

 We have then:

 f (x) = 2 ^ x

 g (x) = f (x) + k

 if k = 2

 then,

 the graph of g (x) is shifted vertically 2 units up