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adam15200031
04.07.2019 •
Mathematics
Afruit stand has to decide what to charge for their produce. they need $ 1 0 $10dollar sign, 10 for 4 44 apples and 4 44 oranges. they also need $ 1 2 $12dollar sign, 12 for 6 66 apples and 6 66 oranges. we put this information into a system of linear equations. can we find a unique price for an apple and an orange?
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Ответ:
Given 4 apples and 4 oranges cost = $10.
6 apples and 6 oranges = $12.
Let us assume cost of each apple = $x.
Cost of each orange = $y.
4 apples and 4 oranges cost can be given by equation:
4x+4y = 10.
Dividing both sides by 4, we get
x+y = 2.50 equation (1)6 apples and 6 oranges cost can be given by equation:
6x+6y = 12.
Dividing both sides by 6, we get
x+y =2 equation (2).We can see from equation (1) and equation (2), that x+y equals 2 and 2.5.
But that doesn't seem to be true.
So, we could just say that we can't find a unique price for an apple and an orange for the given information.Ответ:
A, CA and D
Step-by-step explanation: