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thomaskilajuwon
17.07.2019 •
Mathematics
Agroup of people were surveyed, and the data about their age and whether they have an iron deficiency was recorded in the two-way frequency table. based on the data in the table, the probability of randomly choosing a person who has iron deficiency and is less than 20 years old is 1.) . the probability of randomly choosing a person who does not have iron deficiency and is more than 20 years old is 2.) . chooses for #1 = 1-a.) 0.14 1-b.) 0.27 1-c.) 0.4 chooses for #2 = 2-a.) 0.15 2-b.) 0.23 2-c.) 0.3
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Ответ:
1-A.) 0.14
2-C.) 0.3
Step-by-step explanation:
1.) The number of persons who have iron deficiency and is less than 20 years old =41
The total number of persons surveyed = 3000
Thus, the probability of randomly choosing a person who has iron deficiency and is less than 20 years old![=\frac{41}{300}=0.136666666667\approx0.14](/tpl/images/0098/2575/f14a0.png)
Hence, the probability of randomly choosing a person who has iron deficiency and is less than 20 years old = 0.14
2.) The number of persons who do not have iron deficiency and is more than 20 years old =43+46=89
Thus, the probability of randomly choosing a person who do not have iron deficiency and is more than 20 years old![=\frac{89}{300}=0.296666666667\approx0.30](/tpl/images/0098/2575/a972b.png)
Hence, the probability of randomly choosing a person who do not have iron deficiency and is more than 20 years old =0.3
Ответ:
C:The set of all possible outcomes