Ahemispherical bowl is made of 0.50 cm thick brass. the inner radius of the bowl is 6 cm. find the outer and inner curved surface area and volume of the bowl.

Surface area of Sphere = 4πr²

* The bowl, is half a sphere (hemisphere)

Inside radius, r = 6 cm

inside hemisphere surface area = (1/2)4π(6)²

= 2π36

= 72π

= 226.2 cm²

Outside hemisphere surface area = (1/2)4π(6.5)²

= 2π(42.25)

= 84.5π

= 265.5 cm²

Volume of Sphere = (4/3) πr³

1/2 of this fills the bowl, hemisphere

inside Hemisphere volume = (1/2)(4/3)π(6)³

= (2/3)π(216)

= 144π

= 452.4 cm³

A should be correct.

Step-by-step explanation:

Given, a = 1/2 and b = -1/3

First, let's solve the numerator. Then we have:

1/2 - 1/3

= 1/6

Since we found out our numerator, It is time to find out our denominator.

We have:

1/2 x -1/3

= -1/6

Since we now know the numerator and the denominator, we can now find out what is a+b/ab. We can find that by adding the numerator and denominator.

1/6 divided by -1/6 is equaled to -1.

Therefore, A should be correct.

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