[algebra 1] graph the line with slope -3/4 passing through the point (-3,-3). *will give brainliest answer to the one who gave a full explanation with shown work.

Slope formula is y=mx+b. m is the slope and b is the y-intercept. You can plug the coordinates that are given, (-3,-3), to find the y-intercept.

y=-3/4x+b is the equation you have so far. Plug in (-3,-3):

-3=-3/4(-3)+b

Multiply -3/4*-3.

-3=9/4+b

Subtract 9/4 from both sides.

-21/4=b

Equation: y=-3/4x-21/4

-21/4 equals -5.25, so your y-intercept would be (0,-5.25). That is the first point that you can plot on your graph.

After this, to graph the rest of the equation, you need to use your slope, -3/4. Every point will be down 3, right 4 from the one before it. In this case, your next point to graph would be (4,-8.25). You can also find what the coordinates would be in the opposite direction by going up 3, and left 4 from the original y-intercept. In this case, the coordinates would be (-4, -2.25)

Graph the points: (0,-5.25), (4,-8.25), and (-4, -2.25). Connect all the points to form your line. Normally, graphing two or three points should be enough!

I hope this helps :)

A) ∠BEI ≅ ∠CEH because vertical angles are congruent; rotate ΔCEH 180° around point E, then translate point C to point B to confirm∠IBE ≅ HCE.