Aline has a slope of 0 and passes through the point (7, 8). what is its equation in slope-intercept form?

y=8

Step-by-step explanation:

y-y1=m(x-x1)

y-8=0(x-7)

y-8=0

y=0+8

y=8

It's a horizontal line, y = 8.

We start off with the equation 'y = mx + b'

Since we know that the slope is 0, we input that into m:
y = 0x + b

Input (7, 8) in order to find b:
8 = 0(7) + b
8 = 0 + b
8 = b

And so:
y = 0x + 8

Since the 0 makes x negligible, we can take it out:
y = 8

-T.B.

−3.5x+7−(5.3x−4)Distribute the Negative Sign:=−3.5x+7+−1(5.3x−4)=−3.5x+7+−1(5.3x)+(−1)(−4)=−3.5x+7+−5.3x+4Combine Like Terms:=−3.5x+7+−5.3x+4=(−3.5x+−5.3x)+(7+4)=−8.8x+11=−8.8x+11