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emmalou14
23.01.2020 •
Mathematics
Aline passes through the point (4, –6) and has a slope of negative three-fourths. which is the equation of the line?
a y = negative three-fourths x minus 3
b y = negative three-fourths x minus 6
c y = negative 3 x minus three-fourths
d y = negative 6 x minus three-fourths
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Ответ:
Option A
The equation of line is![y = \frac{-3}{4}x - 3](/tpl/images/0466/8874/d4ada.png)
Solution:
Given that line passes through the point (4, –6) and has a slope of Negative three-fourths
Given point is (x, y) = (4, -6)
The equation of line passing through point (x, y) and slope "m" is given as:
y = mx + c ----- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Substitute (x, y) = (4, -6) and
in eqn 1
The required equation of line is given as:
Thus the equation of line is found
Ответ:
the answer is A
Step-by-step explanation:
Hope this helps!
Ответ:
The Building B is taller than Building A and by 16.354 feet ≈16 feet.
Step-by-step explanation:
Kayson is looking at building A at an angle of elevation of 73° and building A is 30 feet away from him.
So, if the height of the building A is x feet, then we can write,
tan 73°=x/30, ⇒x =30 tan73° =98.125 feet.
Again, Kayson is looking at building B at an angle of elevation of 73° and building B is 35 feet away from him.
So, if the height of the building B is y feet, then we can write,
tan 73° =y/35, ⇒ y= 35 tan73° = 114.479 feet.
Therefore, Building B is taller than Building A and by (114.479-98.125) =16.354 feet ≈16 feet. (Answer)