An airplane is at an elevation of 35,000 ft when it starts its descent at a 20 degree angle of depression. what is the air distance between the airplane and the airport in miles?

19.4 miles

Step-by-step explanation:

Let x represent distance between the airplane and the airport in miles.

We have been given that an airplane is at an elevation of 35,000 ft when it starts its descent at a 20 degree angle of depression. We are asked to find the distance between the airplane and the airport in miles.

We can see that airplane, airport and angle of depression forms a right triangle with respect to ground. The side of 35,000 ft is opposite side and x is hypotenuse to 20 degree angle.

To convert our distance into miles, we will divide 102333.154 by 5280.

Therefore, the air distance between the airplane and the airport is 19.4 miles.

the answer is 25

Step-by-step explanation:

5 + 5 + 5 + 5 + 5 = 25