An analyst for an online shopping site discarded an upper outlier and calculated that the mean number of minutes customers spent on the site was 23 and the median was 26. What effects are likely if the analyst decides to include the upper outlier in the calculations? Check all that apply. The median will stay about the same.
The mean will stay about the same.
The median will decrease.
The mean will increase.
The median will increase.

The median will stay about the same.

The mean will increase.

Step-by-step explanation:

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Polygon Q's area is 1/4 of Polygon P's area

Explanation:

Imagine we had a square with side length 8. The area of this square is 8*8 = 64.

Now let's reduce each side of the square by the scale factor 1/2. So each new side is 8*(1/2) = 4. The area of this smaller square is 4*4 = 16.

Comparing the new area (16) to the old one (64), we see that the new area is 16/64 = 1/4 of the old area.

In other words,

new smaller area = (1/4)*(old larger area)

So this is one example to see why (1/2)*(1/2) = 1/4 is the area scale factor based on the linear scale factor of 1/2. In short, (1/2)^2 = 1/4. Whatever the original scale factor is, square it and you'll get the area scale factor.