An arithmetic sequence a starts 2, 5, . . 1. Use your definition to make a table of values for a (n) and find a (6).
na(n)
1
2
3
4
5
6

Tn = 3n-1

T6 = 17

Step-by-step explanation:

Given the arithmetic sequence;

2, 5...

first term a = 2

Common difference d = 5-2 = 3

nth term of an AP is expressed as Tn = a + (n-1)d

Tn = 2 + (n-1)(3)

Tn = 2 + 3n-3

Tn = 3n-1

Get the 6th term

T6 = 3(6)-1

T6 = 18-1

T6 = 17

Hence the 6th term of the sequence is 17

A

Step-by-step explanation:

common difference d = 4

nth term = a₁ + (n-1)d

= 50 + (n-1)4

= 50 + 4n-4

= 46 + 4n